A suitable JVM could not be found in Linux

Problem: A suitable JVM could not be found. Please run the program again using the option -is: javahome <JAVA HOME DIR>

Problem: The installer is unable to run in graphical mode. Try running the installer with the -console or -silent flag.

Solution: I installed orcle brm same problem occours I will have search in the google but solution in  my point view I missied some libraries.

First everyone install java using:

                                    yum install java

after that install :

                                    yum install libXtst.i686

main thing you can install in GUI mode must run xmanager or xming type of GUI softwares.

Set the putty connections properly:

                 In the putty Enable X11 forwarding correctly

Return value of printf() function in C

Return value of printf() function in C

Ans:

A function always returns a value and printf function returns the number of characters successfully printed.

main() 
{ 
int s=1; 
printf("%d",printf("%d %d %d", s,s,s)); 
}

In this above program the inner printf is first called which prints value of s, three times with space between each value, 1 1 1.

Total 5 characters get printed = 3 values and 2 spaces).

As explained earlier the inner printf after printing the values, returns the number of characters printed, 5 which is printed by the outer printf.

The output of the above program is

1 1 1 5

Most Of The C programming Interview Quesitions With Answers

1.    1. Write a c pgm to print 1 to 100 without using loops.

ANS:1 -100 without looping....

#include
#include
int i=1;
void main()
{
i<=100 ? printf("%d\n",i) : getch(); //conditional operator
i++;
main(); //recursive calling of main() function
}

2.

  Write a c pgm for leap year

#include

int main(){

      intyear;

      printf("Enter a year: ");

      scanf("%d",&year);

      if(year%4== 0)

      {

          if(year%100== 0)/* Checking for a century year */

          {

              if( year%400== 0)

                 printf("%d is a leap year.", year);

              else

                 printf("%d is not a leap year.", year);

          }

          else

             printf("%d is a leap year.", year );

      }

      else

         printf("%d is not a leap year.", year);

      return0;

}

1.    

4.

  Wr 3. fibbonacci series

basic and simple logic fabbonacci series:

#include
#include
void main()
{
int a=1,b=-1,c,n;
printf("enter the no. of terms :");
scanf("%d",&n);
for(int i=1;i<=m;i++)
{
c=a+b;
printf("%d\n",c);
b=a;
a=c;
}
getch();
}

4.write a c pgm for factorial

Factorial :

#include
#include
void main()
{
int m,j=1;
printf("enter ur number :");
scanf("%d",&m);
for(int i=1;i<=m;i++)
j=j*i;
printf("the factorial is : j");
getch();
}

5. Write a c pgm count no of lines , blanks, tabs in a

para(File concept)

#include

void main()
{
FILE *FP;
char Ch;
int l=o,b=0,t=0,p=0;
FP = fopen(filename, mode);
while (FP) {
if(ch==EOF)
break;
l++;
if(ch==" ")
b++;
if(ch=="\n")
p++;
if(ch=="\t")
t++;
fclose(fp);
display counts;
getch();
} 

6. Write a c pgm to print the letter as per given condition

      i.e.. if u give 4

    out put should b

    4 4 4 4

    4 4 4 4

    4 4 4 4

    4 4 4 4

printing ur sequence:

#include
#include
void main()
{
int m;
printf("enter ur number:");
scanf("%d",&m);
for(int i=1;i<=m;i++)
{
for(int j=1;j<=m;j++)
printf("%d ",m);
printf("\n");
}
getch();
}

7.how do get the o/p in number from 1 to 100 in the screen

without using    control statement?

ANS:printing 1-100 without using loops as well as control statement.

#include
#include
int i=1;
void main()
{
i<=100 ? printf("%d\n",i) : getch(); //conditional operator
i++;
main(); //recursive calling of main() function
}

//conditional operator is not a control statement

8. who do u print the word "hello world" without using

"printf" statement?

ANS:printing a string without printf()

#include
#include
void main()
{
if(printf("hello world"))
getch();
}